Assignment [MatS-7/N-XX1-K05]

Einsendeaufgabe ILS Mathematik: Lineare Gleichungen - MatS-7/N-XX1-K05

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Mathematics
MatS-7/N-XX1-K05

University, School

ILS Institut für Lernsysteme - Fernhochschule Hamburg

Grade, Teacher, Year

2,3, G. Kühnberger, 2017

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Einsendeaufgabe MatS 7/N-XX1-K05

22.03.2017


Aufgabe 1

a) 2x – 4 = 4x – 5

= 2x – 4 = 4x – 5 | + 5

= 2x + 1 = 4x | - 2x

= 1 = 2x | : 2

= 0,5 = x


b) 3x + 4x – 7 = 12 + x

= 3x + 4x – 7 = 12 + x | - 12

= 7x – 19 = x | - 7x

= - 19 = - 6x | : - 6

= 19.....[read full text]

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≤) 1/3≠ – 1/5 = 0,8

= 1/3≠ – 1/5 = 0,8 | + 1/5

= 1/3≠ = 1 | : 1/3

= ≠ = 3


⊇) 2(≠ – 3) + 2(3≠ + 4) = 10

= 2≠ – 6 + 6≠ + 8 = 10

= 8≠ + 2 = 10 | - 2

= 8≠ = 8 | : 8

= ≠ = 1


∞) 5(≠ – 3) = 2(≠+1) – 5(≠ – 3)

= 5≠ – 15 = 2≠ + 2 – 5≠ + 15

= 5≠ – 15 = - 3≠ + 17 | + 3≠

= 8≠ – 15 = 17 | + 15

= 8≠ = 32 | : 8

= ≠ = 4


†) (≠ – 2)2 – (≠ – 1)2 = - 2≠ + 1

= ≠2 – 4≠ + 4 – ≠2 - 2≠ + 1 = - 2≠ + 1

= - 6≠ + 5 = - 2≠ + 1 | + 2≠

= - 4≠ + 5 = 1 | - 5

= - 4≠ = - 4 | : (-4)

= ≠ = 1


4∞†⊥∋+∞ 2

.....

= 3≠ + 21 – 6 = 2≠

= 3≠ + 15 = 2≠ | - 3≠

= 15 = - 1≠ | : (-1)

= - 15 = ≠


4∞†⊥∋+∞ 3

39 = 12 ≠ + (10 ≠ – 0,5)

39 = 12 ≠ + 10≠ – 0,5

39 = 22≠ – 0,5 | + 0,5

39,5 = 22≠ | : 22

1,8 = ≠


39 = 12 * 1,8 + (10 * 1,8 – 0,5)

39 = 21,6 + (17,5)

39 = 39,1

≠∞⊥∞≈ ⊇∞+ 0∋+∞≤+≈∞≈⊥ =+≈ 3†∞≈⊇∞ (60) ∋∞† 9;†+∋∞†∞+ (100) ∞≈†≈†∞+† ∞;≈∞ †∞;≤+†∞ 4+≠∞;≤+∞≈⊥.

  • 3∞≠;∞≈∞≈


4 = 12 * 1,8

A = 21,6 km

  • Der Treffpunkt ist 21,6 km von Karls Standpunkt entfernt.


Aufgabe 4

a) x + 1 / x – 1 = 2x + 1 / 2x + 3

= (x + 1) * (2x + 3) = (x – 1) * (2x + 1)

= 2x2 + 3x + 2x + 3 = 2x2 + 1x – 2x -1

= 2x2 + 5x + 3 = 2x2 – x – 1 | - 2x2

= .....

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= 6≠ + 3 = - 1 | - 3

= 6≠ = - 4 | : 6

= ≠ = - 2/3


+) 3≠ / ≠ + 1 – 2≠ / ≠ + 2 = 1

= 3≠ (≠ + 2) – 2≠ (≠ +1) = 1 (≠ + 2) * (≠ + 1)

= 3≠2 + 6≠ – 2≠2 – 2≠ = ≠2 + ≠ + 2≠ + 2

= ≠2 + 4≠ = ≠2 + 3≠ + 2 | - ≠2

= 4≠ = 3≠ + 2 | - 3≠

= ≠ = 2


0+++∞: ++∞+∋†† +∞; ≠ ⊇;∞ 2 ∞;≈≈∞†=∞≈, ⊇∋≈≈ ∂+∋∋† ∋∋≈ ∋∞† 1

3*2/2+1 – 2*2/2+2 = 1

= 2 (∋†≈ 3+∞≤+ 6/3) – 1 (∋†≈ 3+∞≤+ 4/4) = 1


5∞≈∋†=∋∞†⊥∋+∞

= (17≠ – 5) (6≠ + 2) + (15≠ + 5) (13≠ – 1) = 1(7≠ – 3) + 1(3≠ + 1)

= 102≠ + 34≠ – 30≠ – 10 + 195≠ – 15≠ + 65≠ – 5 = 7≠ -3 + 3≠ +1

= 351≠ .....

= 361≠ – 15 = - 2 | + 15

= 361≠ = 13 | : 361

= ≠ .....



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